16a^4-b^8=0

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Solution for 16a^4-b^8=0 equation:


Simplifying
16a4 + -1b8 = 0

Solving
16a4 + -1b8 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add 'b8' to each side of the equation.
16a4 + -1b8 + b8 = 0 + b8

Combine like terms: -1b8 + b8 = 0
16a4 + 0 = 0 + b8
16a4 = 0 + b8
Remove the zero:
16a4 = b8

Divide each side by '16'.
a4 = 0.0625b8

Simplifying
a4 = 0.0625b8

Combine like terms: 0.0625b8 + -0.0625b8 = 0.0000
a4 + -0.0625b8 = 0.0000

Factor a difference between two squares.
(a2 + 0.25b4)(a2 + -0.25b4) = 0.0000

Factor a difference between two squares.
(a2 + 0.25b4)((a + 0.5b2)(a + -0.5b2)) = 0.0000

Subproblem 1

Set the factor '(a2 + 0.25b4)' equal to zero and attempt to solve: Simplifying a2 + 0.25b4 = 0 Solving a2 + 0.25b4 = 0 Move all terms containing a to the left, all other terms to the right. Add '-0.25b4' to each side of the equation. a2 + 0.25b4 + -0.25b4 = 0 + -0.25b4 Combine like terms: 0.25b4 + -0.25b4 = 0.00 a2 + 0.00 = 0 + -0.25b4 a2 = 0 + -0.25b4 Remove the zero: a2 = -0.25b4 Simplifying a2 = -0.25b4 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(a + 0.5b2)' equal to zero and attempt to solve: Simplifying a + 0.5b2 = 0 Solving a + 0.5b2 = 0 Move all terms containing a to the left, all other terms to the right. Add '-0.5b2' to each side of the equation. a + 0.5b2 + -0.5b2 = 0 + -0.5b2 Combine like terms: 0.5b2 + -0.5b2 = 0.0 a + 0.0 = 0 + -0.5b2 a = 0 + -0.5b2 Remove the zero: a = -0.5b2 Simplifying a = -0.5b2

Subproblem 3

Set the factor '(a + -0.5b2)' equal to zero and attempt to solve: Simplifying a + -0.5b2 = 0 Solving a + -0.5b2 = 0 Move all terms containing a to the left, all other terms to the right. Add '0.5b2' to each side of the equation. a + -0.5b2 + 0.5b2 = 0 + 0.5b2 Combine like terms: -0.5b2 + 0.5b2 = 0.0 a + 0.0 = 0 + 0.5b2 a = 0 + 0.5b2 Remove the zero: a = 0.5b2 Simplifying a = 0.5b2

Solution

a = {-0.5b2, 0.5b2}

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